The heat load if the above calculation is correct will be ~60 watts at full power. So think of a 60-75 watt light bulb.
On the plus side for cooling this is a relatively open frame motor made largely of aluminum with an outrunner spinning around, and the bike is traveling, so in early tests just put a hand on the motor perodically -- the best temperature gauge for this kind of thing. And if it feels hot, add a fan.
Steve you mentioned questions about motor torque. Given the RPM and assumed power, seems it should be possible to solve for torque. Looking it up on the internet I found the equation:
power = torque x 2pi x rotational speed
so
torque = power(watts)/ (revs per sec * 2pi)
so
torque = 500/ (5700/60 * 6.28)
torque = .84 Newton meters (or .62 foot pounds)
A 26" wheel at 30 mph is doing 388 rpm (if I also got that right --- better check that, too) so your final reduction is maybe 5700/388 or 14.7 to 1.
If you had a 3 to 1 sprocket ratio on the chain drive, your gearbox ratio would be 14.7 / 3 or about 5 to 1.
So torque out of the gear box would be about 5 x .84 = 4.2 Nm or 3.1 ft lbs at that speed.
Could be a lot of incorrect assumptions or outright units blunders here..... take with a grain of salt!
